Phil said that people have no idea how much power they lose to enclosed tracks because water has to suck into the track behind the departing shaft, and a low pressure area is created that retards forward travel of the shaft.
This is one of those things that I have pondered, and always wished I could see some high speed camera footage of.
For example, I think Don Paul has mentioned boat-tailing the ends of the shaft to reduce drag. I wonder if there is cavitation behind the shaft? If there is cavitation, then how does the vapor space impact the significance of water having to fill the void throught the top of the track?
Someone who is more current in fluid dynamics will have to help me out on this, but the low pressure area behind the shaft couldn't possibly be stronger than a full vacuum (14.7 psi) right? So given that the area of a 5/16" shaft is 0.08 square inches, aren't we talking about a maximum of about 1.1 lbs of resistance?
None of which is to suggest that enclosed tracks don't sap energy, and probably in multiple ways (increased friction area, wedging of a momentarily distorted shaft, etc.). I'm just trying to work out the scenario that Bill mentioned.
Edit - I just realized that the low pressure theory would be pretty easy to test on a gun with a Neptonics enclosed plastic track. That would make it easy to change out the track, while keeping everything else about the gun the same. I can envision three tests - An open track, an enclosed track with the normal openning on top, and an enclosed track with the openning cut as large as it could possibly be and still retain the shaft.