I just read few articles and I have made a formula to calculate the required lead+Stainless work for primary balancing I hope someone will check and correct me if I'm wrong
required mass of (lead+SS) in Kg =(buouancy force newton/9.8)= denisty of water * (volum of displaced water =volum of wood )
is it OK ?
for example
wood mass is 1.51 Kg
wood volume is 0.00204 m3
teak density is 740 kg/m3
water density =1035 kg/m3
required mass of lead +SS = 2.11 kg
if your SS works is 0.9 kg u need approximate 1.2 Kg lead
required mass of (lead+SS) in Kg =(buouancy force newton/9.8)= denisty of water * (volum of displaced water =volum of wood )
is it OK ?
for example
wood mass is 1.51 Kg
wood volume is 0.00204 m3
teak density is 740 kg/m3
water density =1035 kg/m3
required mass of lead +SS = 2.11 kg
if your SS works is 0.9 kg u need approximate 1.2 Kg lead
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